Dr. Finan's study guide is an excellent resource for those preparing to take Actuarial Exam 1/P on probability.
Problems that require numerical answers are answered here, but it is still the responsibility of the student to provide his or her own work for these problems. These answers are meant to enable students to independently verify the correctness of their reasoning by checking to see if the end result they obtained is correct. Questions from the study guide that require proofs or diagrams are not addressed here, as the end result of those questions is known in advance, and it is the responsibility of the student to provide the procedure for getting there.
Section 17.
Answer 17.1. 0.45= 45%.
Answer 17.2. 374.4
Answer 17.3a. c= 1/55
Answer 17.3b. E(X) = -12/11= about -1.090909090909;Var(X)= 644/605= about 1.06446281
Answer 17.4a. p(x)=
1/30 for x=1,
3/10 for x=2,
½ for x=3,
1/6 for x=4,
0 otherwise
Answer 17.4b. E(X)= 2.8; Var(X)= 0.56
Answer 17.5a. c=1/30
Answer 17.5b. E(X)= 10/3; E(X(X-1))= 127/15
Answer 17.5c. Var(X)= 31/45 = about 0.6888889
Answer 17.6. E(Y)=21; Var(Y)= 144
Answer 17.7b. 4/7= about 0.5714285714
Answer 17.7c. p(X)=
0.24 for x=7,
0.16 for x=8,
0.18 for x=12,
0.42 for x=15
Answer 17.7d. E(X)= 11.42; Var(X)= 12.0036
Answer 17.8a. p(x)=
4/7, for x= -1,
3/7 for x=2
Answer 17.8b. E(X)= 2/7= about 0.2857142857; E(X2) = 16/7= about 2.2857142857
Answer 17.8c. Var(X)= 108/49= about 2.204081633
Answer 17.9. Var(X)= 9.86; SD(X)=about 3.136877428
Answer 17.10. E(X) = p; Var(X) = p(1-p)
See a list of all the answer keys to Dr. Finan's study guide for Exam 1/P here.
Published by G. Stolyarov II
G. Stolyarov II is a science fiction novelist, independent essayist, poet, amateur mathematician, composer, author, and actuary. View profile
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1 Comments
Post a Commentanswer 17.9 var(x) seems to be 9.84 instead of 9.86