Discrete Temporary Life Annuities: Practice Problems and Solutions
The Actuary's Free Study Guide for Exam 3L - Section 42
It is possible to find the actuarial present value of a discrete whole life annuity-immediate as follows:
ax = (1 - (1+i)Ax)/i, where i is the annual effective interest rate and Ax is the actuarial present value of a whole life insurance policy with benefits payable at the end of the year of death.
The actuarial present value of a discrete n-year temporary life annuity-due is denoted as äx:n¬and can be found via the following formula.
äx:n¬= k=0n-1Σvk*kpx
The actuarial present value of a discrete n-year temporary life annuity-immediate is denoted as ax:n¬and can be found via the following formula.
ax:n¬= k=1nΣvk*kpx
The following relationships hold:
äx:n¬= 1 + ax:n-1¬
If Y is the present-value random variable for a discrete n-year temporary annuity-due, then
Var(Y) = [2Ax:n¬ - (Ax:n¬)2]/d2, where d = r/(1+r) and Ax:n¬is the actuarial present value of an n-year endowment insurance policy paying one unit in benefits at the end of the year of death.
Source: Bowers, Gerber, et. al. Actuarial Mathematics. 1997. Second Edition. Society of Actuaries: Itasca, Illinois. pp. 145-148.
Original Problems and Solutions from The Actuary's Free Study Guide
Problem S3L42-1. The life of a triceratops has the following survival function associated with it: s(x) = e-0.34x. The annual force of interest in Triceratopsland is currently 0.06. Eduardo the Triceratops is currently 14 years old and takes out a discrete 5-year life annuity-due paying a benefit of 1 Golden Hexagon (GH) at the beginning of each year. Find the actuarial present value of this annuity.
Solution S3L42-1. We use the formula äx:n¬ = k=0n-1Σvk*kpx. Since the lifetimes of triceratopses are exponentially distributed, kpx = e-0.34k for all x. Moreover, vk = e-0.06k. Thus, for n = 5,
ä14:5¬ = k=04Σe-0.06k*e-0.34k = k=04Σe-0.4k = 1 + e-0.4 + e-0.8 + e-1.2 + e-1.6 = about 2.62273974 GH.
Problem S3L42-2. Odaroloc the Colorado Beetle has a whole life insurance policy with benefits payable at the end of the year of death, whose actuarial present value is 0.92 Golden Hexagons (GH). The annual effective interest rate is 0.03. Odaroloc wishes to purchase a discrete whole life annuity-immediate from an actuarially fair insurance provider. How much will he have to pay for the annuity?
Solution S3L42-2. We use the formula ax = (1 - (1+i)Ax)/i, where we are given i = 0.03 and Ax = 0.92. Thus, ax = (1 - 1.03*0.92)/0.03 = ax = about 1.746666666667 GH.
Problem S3L42-3. The life of a yellow whale has the following survival function associated with it: s(x) = e-0.07x. The annual force of interest is currently 0.02. Wolley the Yellow Whale is currently 34 years old and takes out a discrete 17-year temporary life annuity-immediate paying a benefit of 1 Golden Hexagon (GH) at the end of each year. Find the actuarial present value of this annuity.
Solution S3L42-3. We use the formula ax:n¬ = k=1nΣvk*kpxfor n = 17. Since the lifetimes of yellow whales are exponentially distributed, kpx = e-0.07k for all x. Moreover, vk = e-0.02k. Thus,
a34:17¬ = k=117Σe-0.02k*e-0.07k = k=117Σe-0.09k = e-0.09(1 - e-0.09*17)/(1 - e-0.09) = a34:17¬ = about 8.319302275 GH.
Problem S3L42-4. A 12-year-old swimming squirrel can get a 4-year discrete temporary life annuity-immediate for 34 Golden Hexagons (GH). It can also get a 15-year discrete temporary life annuity-due for twice the actuarial present value of a 5-year discrete temporary life annuity-due. How much will the swimming squirrel have to pay for the 15-year annuity?
Solution S3L42-4. We use the formula äx:n¬ = 1 + ax:n-1¬ to find ä12:5¬ = 1 + a12:4¬ = 1 + 34 = 35.
We are also given ä12:15¬ = 2ä12:5¬ = 2*35 = ä12:15¬ =70 GH.
Problem S3L42-5. Elteeb the Colorado Beetle can get a 6-year endowment insurance policy paying one unit in benefits at the end of the year of death for 0.67 Golden Hexagons (GH). The second moment of the present value of this policy is 0.55. The annual effective interest rate is 0.03. Find the variance of the present value of a discrete 6-year temporary annuity-due available to Elteeb.
Solution S3L42-5. We use the formula Var(Y) = [2Ax:n¬ - (Ax:n¬)2]/d2 =
[2Ax:n¬ - (Ax:n¬)2]/(i/(1+i))2
We are given i = 0.03, 2Ax:7¬ = 0.55, and Ax:7¬ = 0.67.
Thus, Var(Y) = (0.55 - 0.672)/(0.03/1.03)2 = Var(Y) = about 119.1744333.
See other sections of The Actuary's Free Study Guide for Exam 3L.
Published by G. Stolyarov II
G. Stolyarov II is a science fiction novelist, independent essayist, poet, amateur mathematician, composer, author, and actuary. View profile
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3 Comments
Post a Commenthi does anyone here knowd how to get the variance oh Loss at time t of an h payment n year endowment? thank you
Mr. Meyerson, thank you for pointing that out. The correction has been issued.
In the third question, you sum up e^(-.09k) over k ranging from 1 to 17 and get
e^-.09 (1 - e^(-.09 * 18))/(1 - e^(-.09)); however, this is actually the sum over k ranging from 1 to 18 (the '18' should instead be replaced by a '17').